Posted by **Anonymous** on Sunday, December 26, 2010 at 6:07pm.

Reaction H2 +I2 yields 2HI

All three gases are initially at 0.1atm/ upon reaching equilibrium it is found that H2 pressure droped by 55% what is the equilibrium constant for this reaction.

- chem -
**bobpursley**, Sunday, December 26, 2010 at 7:10pm
if pressure dropped by 55 percent, then the new concentration is 45 precent of the original. I assume you mean Partial pressure of the H2 dropped by 55 percent.

Pressure is directly related to concentration.

keq= [HI]^2/[H2][I2]

keq=(.1+2x)^2/(.1-x)(.1-x)

but .1-x= .55(.1) or x=.1-.055=.045

which means

keq=(.1+2*.045)^2/.055^2=11.9 check my math and thinking.

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