Q:a)the number 10 to the power 100 (10000 sexdecillion) is called a googol! if it takes 1/5 second o write a zero and 1/10 sec to write a 'one',how long would it take to write a number 100 googols in full?
b)the number 10 to power of a googol is called a googolplex.using the same speed of writing,how long in years would it take to write 1 googolplex in full?you may assume that ur pen has enough ink.
I hate it
whats the answer for part (a)
a) To calculate the time it would take to write a number with 100 googols in full, we need to sum up the time it takes to write each digit individually.
For a single zero, it takes 1/5 of a second, and for a single one, it takes 1/10 of a second.
Considering that a googol has 101 digits (since 10^100 has 101 digits), we can break it down as follows:
- There are 100 zeros (since the number is 10 to the power of 100).
- There is one one at the end.
So, the total time it takes to write a number with 100 googols in full can be calculated as follows:
100 zeros * 1/5 second + 1 one * 1/10 second = 100/5 + 1/10 = 20 + 0.1 = 20.1 seconds
Therefore, it would take approximately 20.1 seconds to write a number with 100 googols in full.
b) To calculate the time it would take to write a googolplex, we need to know how many digits a googolplex has.
A googolplex is 10 to the power of a googol. Since a googol has 101 digits, a googolplex would have 10^101 digits.
Given that the time it takes to write a single digit is the same as in the previous question, we can calculate the time it takes to write a googolplex:
10^101 digits * (1/5 second per zero + 1/10 second per one) = 10^101 * (1/5 + 1/10) seconds
To convert this into years, we can divide the result by the number of seconds in a year:
10^101 * (1/5 + 1/10) / (365.25 * 24 * 60 * 60) ≈ 1.901 × 10^88 years
Therefore, it would take approximately 1.901 × 10^88 years to write a googolplex in full.
b) 10^100 times? what is 1/5sec+(1/10)*10^100 seconds?
.2+ .1*10^100=.2+10^99 seconds.
now, in years.
time= (.2+10^99)sec*1hr/3600sec*1day/24hr*1yr/365.25days= you do it. I would drop the .2 second term.