Saturday

March 28, 2015

March 28, 2015

Posted by **jay** on Friday, December 24, 2010 at 8:54pm.

highway.

The acceleration of gravity is 9.81 m/s

2. a) If the coeﬃcient of kinetic friction between the road and the tires on a rainy day is

0.116, what is the minimum distance needed

for the car to stop

b) What is the stopping distance when the

surface is dry and the coeﬃcient of kinetic

friction is 0.698

- physics -
**drwls**, Friday, December 24, 2010 at 9:50pmFirst of all, convert 55.1 km/h to 15.3 m/s

2a) The stopping distance X is given by this equation that relates the kinital kinetic energy to the work done against friction:

(1/2)M V^2 = M*g*Uk*X

Notice that the mass M cancels out, which is good since they did not tell you the mass.

X = V^2/(2*g*Uk) = 103 m

2b) Use the same formula, but with the different value of Uk (the kinetic friction corefficient). The stopping distance is much less.

**Answer this Question**

**Related Questions**

physics - A car is traveling at 58.2 km/h on a ﬂat highway. The ...

Physics - A 1500 kg car moves along a horizontal road at speed v0 = 21.9 m/s. ...

Physics - A curve of radius 40 m is banked so that a 1070 kg car traveling at 60...

physics - A curve of radius 20 m is banked so that a 970 kg car traveling at 50 ...

AP Physics - To test the performance of its tires, a car travels along a ...

Phys - i cant get this no matter what i try; A curve of radius 40 m is banked so...

physics - Once a 28 kg crate is in motion on a horizontal ﬂoor, a ...

physics - Once a 15 kg crate is in motion on a horizontal ﬂoor, a ...

Physics - Once a 15 kg crate is in motion on a horizontal ﬂoor, a ...

Phyisics - Once a 26 kg crate is in motion on a horizontal ﬂoor, a ...