Posted by Bashr on Friday, December 24, 2010 at 10:37am.
let L = wavelength, A = amplitude and w = angular frequency
max particle velocity = w A
wave speed = 2 pi w L
ratio (part speed)/(wave speed)
= A/(2 pi L)
Note that the ratio is independent of wave speed, w and cord tension. It would have been necessary to know these parameters to compute either speed.
Can you please relook at the question , the answer I get using the equation you provided did not work .Thank you anyway
A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength = 3.4 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.
The answer I got is 0.14979288 ( using A/(2 pi L) )
frequency*wavelength=wavespeed
w/2PI * L= wL/2PI
check that.
Thanks Bob. I put the 2 pi in the wrong place.
Thanks alot guys :)
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