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March 28, 2017

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A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength = 3.4 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.

  • physics - ,

    let L = wavelength, A = amplitude and w = angular frequency

    max particle velocity = w A
    wave speed = 2 pi w L

    ratio (part speed)/(wave speed)
    = A/(2 pi L)

    Note that the ratio is independent of wave speed, w and cord tension. It would have been necessary to know these parameters to compute either speed.

  • physics - ,

    Can you please relook at the question , the answer I get using the equation you provided did not work .Thank you anyway

    A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength = 3.4 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.
    The answer I got is 0.14979288 ( using A/(2 pi L) )

  • physics - ,

    frequency*wavelength=wavespeed
    w/2PI * L= wL/2PI

    check that.

  • physics - ,

    Thanks Bob. I put the 2 pi in the wrong place.

  • physics - ,

    Thanks alot guys :)

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