Posted by Tarkan on Thursday, December 23, 2010 at 9:54pm.
NaOH ==> Na^+ + OH^-
NaOH is 0.04M from the problem.
Na^+ is 0.04M and OH^- is 0.04M
You took the -log(OH^-), which is 1.40 and you called that the H^+ but it isn't. It is the (OH^-) so you calculated the pOH and not the pH. But you can convert your pOH to pH from the equation
pH + pOH = pKw = 14.00
pH + 1.40 = 14.00
pH = 14.00 - 1.40 = 12.60
Related Questions
Chemistry - What will be the pH of an aqueous solution containing 0.040 mol/L ...
Chemistry - How much carbon dioxide has to be bubbled into aqueous sodium ...
chemistry - a pH meter gives a readout of 9.35 when the probe is dipped into an ...
chemistry help plzzz - how can i calculate the pH of the solution obtained when ...
Chemistry - Write the balanced chemical equation for each of these reactions. ...
chemistry - Write the balanced chemical equation for each of these reactions. ...
chemistry - a sodium hydroxide solution was prepared according to the procedure ...
Chemistry - Aqueous sulfurous acid (H2SO3) was made by dissolving .200L of ...
chemistry - What is the molarity (mol/L) of sodium (Na) in a solution containing...
Chemistry - What are the concentrations of the following solutions: a) a 200mL ...
For Further Reading