math
posted by Andy .
A student claims that every prime greater than 3 is a term in the arithmetic sequence whose nth term is 6n + 1 or in the arithmetic sequence whose nth term is 6n  1. Is this true? if so, why?

Yes, it is true.
All PRIME numbers above 3 are of the form 6n − 1 or 6n + 1, because all other numbers are divisible by 2 or 3.
That is, the other numbers above 3 (that cannot be written as 6n1 or 6n+1) can be written 6n, 6n+2, 6n+3, or 6n+4. All of those are divisible by 2 or 3 and therefore cannot be prime.
(6n+5 can be written 6(n+1)1 where n+1 is the next integer)