Wednesday

April 23, 2014

April 23, 2014

Posted by **MATH 115 SEC. 8.5 PG 646** on Wednesday, December 22, 2010 at 7:38pm.

0.10,0.18,0.20,0.21,0.24,0.24,0.25,0.26,0.28

What I did was place them in order and worked my way from both end until I got in the middle I came up with 0.24 but not sure if it's right

- ALGEBRA -
**Ms. Sue**, Wednesday, December 22, 2010 at 7:48pm0.24 is the median.

The interquartile range is between the 1st and 3rd quartiles.

Check this site for figuring the IQR.

http://wiki.answers.com/Q/What_is_the_interquartile_range

- ALGEBRA -
**bobpursley**, Wednesday, December 22, 2010 at 7:49pm9 terms, so median is 24

first quartile .19

third quartile .255

IQR= .255-.19=.065 or .07

- ALGEBRA -
**MATH 115 SEC. 8.5 PG 646**, Wednesday, December 22, 2010 at 8:09pmthank you both Ms. Sue for the site and bobpursley for assisting me in this problem.

- ALGEBRA -
**Ms. Sue**, Wednesday, December 22, 2010 at 8:20pmYou're welcome.

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