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Posted by on Wednesday, December 22, 2010 at 2:13pm.

A man of mass M kg and his son of mass m kg are standing in a lift. When the lift is accelerating upwards with magnitude 1ms-2 the magnitude of the normal contact force exerted on the man by the lift floor is 880N. When the lift is moving with constant speed the combined magnitude of the normal contact forces exerted on the man and the boy by the lift floor is 1000N. Find the values of M and m.

  • Mechanics (Physics) - , Wednesday, December 22, 2010 at 2:43pm

    forceonman=880=Mg+ma=M(9.8+1)
    forceonmanconstantspeed=1000=(M+m)g

    well, from the Man data, M = 880/(10.8)

    put that into the second equation, and solve for m, the son mass.

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