anyone who knows the answer to this question please show your work.

drwls i know i posted this queestion before but you didn't reply to my comment.

Your friend has climbed a tree to a height of 6.00 m. You throw a ball vertically up to her and it is traveling at 5.00 m/s when it reaches her. What was the speed of the ball when it left your hand if you released it at a height of 1.10 m?

Initial KE= change in PE+finalKE

1/2 m vi^2=mgh + 1/2 m vf^2 where h is the difference in heights, ie (6.00-1.10)m
solve for vi
solve for vi

i still don't understand:( what is mgh and what is PE??? what is m? i don't understnad many of the variables in this equation. i was never taught this in class neither have i ever heard of this equation. im sorry mr.pursley. i really am.

I would drop your class, you are being cheated.

M mass
g acceleration due to gravity
h distance, or change in height
mgh is potential energy (PE)

If these are not in your text, or never had this in class, or have never heard of it, something is wrong. Either you are lost, or the class is going to la la land, at any rate, you are not learning physics.

idk somehow i am doing well.

d = 6.0 - 1.1 = 4.9m.

Vf^2 = Vo^2 + 2gd = 5^2,
Vo^2 + 2(-9.8)4.9 = 25,
Vo^2 - 96.04 = 25,
Vo^2 = 25 + 96.04 = 121.04,

Vo = sqrt(121.04) = 11m/s.

To find the speed of the ball when it left your hand, we can use the principles of conservation of energy.

Here are the steps to solve the problem:

1. Identify the relevant information:
- Initial velocity of the ball when it left your hand = ?
- Final velocity of the ball when it reached your friend = 5.00 m/s
- Height at which the ball was released = 1.10 m
- Height at which your friend is located = 6.00 m

2. Calculate the potential energy at the release height:
- Potential energy (PE) = mass * gravitational acceleration * height
- In this case, we are only interested in the relative potential energy difference, so we can ignore the mass of the ball.
- PE at release height = 0 (since the reference point for potential energy can be chosen arbitrarily)

3. Calculate the potential energy at the height of your friend:
- PE at friend's height = mass * gravitational acceleration * height
- Again, we can ignore the mass of the ball since the relative potential energy difference is what matters.
- PE at friend's height = m * g * 6.00 m

4. Calculate the change in potential energy:
- Change in PE = PE at friend's height - PE at release height
- Change in PE = m * g * 6.00 m

5. Convert the potential energy change into kinetic energy change:
- Change in KE = - Change in PE (due to the conservation of energy)
- Change in KE = - (m * g * 6.00 m)

6. Calculate the kinetic energy at the release point:
- KE at release point = 0 (since the ball starts from rest)

7. Calculate the kinetic energy at the height of your friend:
- KE at friend's height = (1/2) * mass * velocity^2
- We are given that the final velocity at the friend's height is 5.00 m/s, so we can use this information to solve for the mass of the ball.
- KE at friend's height = (1/2) * m * (5.00 m/s)^2

8. Calculate the change in kinetic energy:
- Change in KE = KE at friend's height - KE at release point
- Change in KE = (1/2) * m * (5.00 m/s)^2

9. Set the change in potential energy equal to the change in kinetic energy:
- - (m * g * 6.00 m) = (1/2) * m * (5.00 m/s)^2
- Solve this equation for the mass of the ball.

Given the mass of the ball, you can use the change in potential energy equation to find the initial velocity at which you released the ball.