Post a New Question

trig

posted by .

Find the value of secant theta for angle theta in standard position if a point with coordinates (-3/4) lies on its terminal side

  • trig -

    When in STD position, the center i8s at
    the origin:

    C(h , k),
    C(0 , o), P(-3 , 4),

    r^2 = (x - h)^2 + (y - k)^2,
    r^2 = (-3 - 0)^2 + (4 - 0)^2,
    r^2 = 9 + 16 = 25,

    r = 5.

    rcos(theta) = x -h = -3 -0 = -3,
    5cos(theta) = -3,
    cos(theta) = -3/5 = -0.6,
    theta = 126.9 deg.

    Sec(theta) = 1/cos(theta) = 1/-0.6 =
    -1.67.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question