trig
posted by Mallory .
Find the value of secant theta for angle theta in standard position if a point with coordinates (3/4) lies on its terminal side

When in STD position, the center i8s at
the origin:
C(h , k),
C(0 , o), P(3 , 4),
r^2 = (x  h)^2 + (y  k)^2,
r^2 = (3  0)^2 + (4  0)^2,
r^2 = 9 + 16 = 25,
r = 5.
rcos(theta) = x h = 3 0 = 3,
5cos(theta) = 3,
cos(theta) = 3/5 = 0.6,
theta = 126.9 deg.
Sec(theta) = 1/cos(theta) = 1/0.6 =
1.67.