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Physics

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A 2.00-kg block of ice is at STP (0¢XC, 1 atm) while it melts completely to water. What is its change in entropy? (For ice, Lf = 3.34 „e 105 J/kg)

  • Physics - ,

    The entropy change, which is an increase in this case, equals the heat of fusion of water divided by the absolute temperature, 273 K.

    I do not understand your
    ¢X and „e symbols. You should precede exponents with a ^

  • Physics - ,

    The c with the line through it is a degree symbol, and the e is a ^ symble. I am sorry the computer put it in that way.

  • Physics - ,

    The answer is 2450 J/K but I can't figure out how to get that.

  • Physics - ,

    You have to multiply by the number of kg also. (heat of fusion)/T gives you the entropy per unit mass

    3.34*10^5 J/kg * 2.00 kg /273 K = 2450 J/K, to three significant figures

  • Physics - ,

    Thank You

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