Posted by **anton** on Sunday, December 19, 2010 at 7:11pm.

evaluate

integral of |x+1| going from -3 to 2.

i.e

2

∫ |x+1| = ?

-3

## Answer this Question

## Related Questions

- Calculus - Evaluate the following definite integral: integral at a = -1, b=2 -...
- Calculus. I need help! - Evaluate the indefinite integral (a.)∫√(...
- COLLEGE CALCULUS. HELP! - Evaluate the definite integral ∫(0,2) (x-1)^25 ...
- Calculus - Evaluate the triple integral ∫∫∫_E (x+y)dV where E ...
- Calculus - Evaluate the triple integral ∫∫∫_E (x)dV where E is...
- Calculus - Evaluate the triple integral ∫∫∫_E (xy)dV where E ...
- Calculus - Evaluate the triple integral ∫∫∫_E (z)dV where E is...
- Calculus - Evaluate the triple integral ∫∫∫_E (xyz)dV where E ...
- Calculus - Evaluate the triple integral ∫∫∫_E (x^2.e^y)dV ...
- calculus I integral - Is this correct? Evaluate 2x∫1 3t(t^2 + 1)^2 dt u= t...