A 70 kg man weighs 686 N on the Earth's surface. How far above the surface of the Earth would he have to go to "lose" 14% of his body weight?
i don't even know where to start with this question... i need help!
physics - Damon, Sunday, December 19, 2010 at 6:45pm
.86 = Rearth^2/r^2
W = G m M/R^2
and G m M does not change
remember that they really ask for
the distance above ground, not the bigger radius from earth center
physics - lissa, Sunday, December 19, 2010 at 7:12pm
could try and explain more in depth? like wat does W stand for? his weight? and i don't really get how your solving it..
physics - Ventz, Monday, December 5, 2011 at 10:52pm
G- gravitational constant
m1- mass on earth
m2- mass of object
r- radius on earth plus given distance over it
.86*686=589.96 to find final force
plug in everything..
Solve for h!