Posted by lissa on Sunday, December 19, 2010 at 6:27pm.
Four identical masses of 2.7 kg each are located at the corners of a square with 1.4 m sides. What is the net force on any one of the masses?
F=((G)(m1)(m2))/r^2
I don't understand why im not getting it right... i need help please!!

physics  Damon, Sunday, December 19, 2010 at 6:42pm
Fopposite corner = G m^2/(1.4*sqrt2)^2
lined up with diagonal
get component along diagonal for the two adjacent sides, thus cos 45 = 1/sqrt2
Fadjacent corners = 2 G m^2 cos 45/1.4^2
= 2 G m^2 (1/sqrt 2) /1.4^2
sqrt 2 is about 1.4 so
F = G m^2 /4 + 2sqrt 2 G m^2/4
(2.
= G m^2 (1+2.8)/4
pretty close to G m^2 but do the arithmetic more accurately than I did in my head
Answer This Question
Related Questions
 physics  Four identical masses of 3.4 kg each are located at the corners of a ...
 physics  Four identical masses of 2.7 kg each are located at the corners of a ...
 physics  Four identical masses of 2.6 kg each are located at the corners of a ...
 physics  Four identical masses of 3.5 each are located at the corners of a ...
 Physics  Four identical masses of 800kg each are placed at the corners of a ...
 Physics  Four identical masses of mass 900 kg each are placed at the corners of...
 physics  Four identical masses of mass 800kg each are placed at the corners of ...
 phys  Four point masses are at the corners of a square whose side is 20 cm long...
 Physics: Three Identical Masses  Three identical masses of 640 each are placed ...
 physics  Four point charges are located at the corners of a square with sides ...
More Related Questions