Posted by **lissa** on Sunday, December 19, 2010 at 6:27pm.

Four identical masses of 2.7 kg each are located at the corners of a square with 1.4 m sides. What is the net force on any one of the masses?

F=((G)(m1)(m2))/r^2

I don't understand why im not getting it right... i need help please!!

- physics -
**Damon**, Sunday, December 19, 2010 at 6:42pm
Fopposite corner = G m^2/(1.4*sqrt2)^2

lined up with diagonal

get component along diagonal for the two adjacent sides, thus cos 45 = 1/sqrt2

Fadjacent corners = 2 G m^2 cos 45/1.4^2

= 2 G m^2 (1/sqrt 2) /1.4^2

sqrt 2 is about 1.4 so

F = G m^2 /4 + 2sqrt 2 G m^2/4

(2.

= G m^2 (1+2.8)/4

pretty close to G m^2 but do the arithmetic more accurately than I did in my head

## Answer this Question

## Related Questions

- physics - Four identical masses of 3.4 kg each are located at the corners of a ...
- physics - Four identical masses of 2.7 kg each are located at the corners of a ...
- physics - Four identical masses of 2.6 kg each are located at the corners of a ...
- physics - Four identical masses of 3.5 each are located at the corners of a ...
- Physics - Four identical masses of 800kg each are placed at the corners of a ...
- Physics - Four identical masses of mass 900 kg each are placed at the corners of...
- physics - Four identical masses of mass 800kg each are placed at the corners of ...
- phys - Four point masses are at the corners of a square whose side is 20 cm long...
- Physics: Three Identical Masses - Three identical masses of 640 each are placed ...
- Physics - Four charges are located at the corners of a square as shown below. ...

More Related Questions