Posted by Elisa on Sunday, December 19, 2010 at 4:49pm.
distance= integral v(t) dt for 2 to 6
= INT (t-64/t^2)dt= t^2+64/t
put in the limits 6,2
do you mean
(t-64)/t^2 maybe
or
t - (64/t^2) as you typed it
???
its --> t - (64/t^2)
could you please solve it..
Ok, that is what I did.
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