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September 16, 2014

September 16, 2014

Posted by **Elisa** on Sunday, December 19, 2010 at 4:49pm.

- Please help - math -
**bobpursley**, Sunday, December 19, 2010 at 4:53pmdistance= integral v(t) dt for 2 to 6

= INT (t-64/t^2)dt= t^2+64/t

put in the limits 6,2

- Watch your parentheses -
**Damon**, Sunday, December 19, 2010 at 4:55pmdo you mean

(t-64)/t^2 maybe

or

t - (64/t^2) as you typed it

???

- Please help - math -
**Elisa**, Sunday, December 19, 2010 at 5:00pmits --> t - (64/t^2)

could you please solve it..

- Please help - math -
**bobpursley**, Sunday, December 19, 2010 at 5:03pmOk, that is what I did.

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