Find the area enclosed by y = 1/x , y = 1/3x , x=3 and x=4

y=f1(x)=1/x

y2=1/3x

area= int (1/x - 1/3x)dx from x=3 to 4

area= lnx -1/3 lnx frm 3,4
area= 2/3 (ln4-ln3)

check my work