Saturday

April 19, 2014

April 19, 2014

Posted by **Dan** on Sunday, December 19, 2010 at 2:34pm.

vertical asymptotes.

- Math -
**MathMate**, Sunday, December 19, 2010 at 8:13pmStationary points are points at which f'(x)=0 AND f"(x)=0.

Vertical asymptote is where the denominator becomes zero.

Horizontal asymptote is the limit when x->∞ or x->-∞, if the limit is defined.

- Math -
**Dan**, Sunday, December 19, 2010 at 9:00pmcould you please solve the problem completely .. i am still confused.

Thanks.

- Math -
**MathMate**, Tuesday, December 21, 2010 at 10:47amDenominator becomes zero when x=3, therefore vertical asymptote is a x=3.

The limit of f(x)=[(x-5)/(x-3)]^2 as x->±∞ is 1, so the horizontal asymptote is at y=1.

Since f'(5)=0 and f"(6)=0, there are no stationary points, just a minimum at x=5.

There is a point of inflection at x=6 (where f"(6)=0).

You will need to take the time to calculate f'(x) and f"(x) from f(x), and hence sketch the graph of f(x).

A sketch of the graph can be seen here:

http://img718.imageshack.us/img718/4296/1292787276.png

**Related Questions**

calc - Given [(x-5)/(x-3)]^2 . Find any stationary points and any points of ...

Calculus - Sketch the graph of f(x)=-x^4 + 4x^3 - 16x + 16: Find the critical ...

Calculus - Sketch the graph of f(x)=x+2/x-4. Find the vertical and horizontal ...

Calculus (urgent!!) - Please answer the following questions about the function f...

Calculus (pleas help!!!) - Please answer the following questions about the ...

Calculus (pleas help!!!) - Please answer the following questions about the ...

Calculus - Sketch the graph of f(x)=(x^2 + 2)/x^2 - 4. Fund the vertical and ...

calculace - G(x)= x√9-x find x-intercept, y-intercept Vertical, ...

College Algebra HELP - Use the seven step method described in the book to graph ...

Seven step method - Use the seven step method described in the book to graph the...