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March 27, 2015

March 27, 2015

Posted by **Dan** on Sunday, December 19, 2010 at 2:10pm.

- Math -
**Damon**, Sunday, December 19, 2010 at 2:27pmf' = 4 x^3 -8 x = 4x (x^2-2)

zero at x = 0 and x = sqrt 2 and x=-sqrt 2

f" = 12 x^2 - 8

at zero this is -8 so a maximum

at +sqrt 2 this is +16

same at -sqrt2 so those are minima

Huge positive for x large positive and for x large negative

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