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March 28, 2017

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Find the average value of f (x)= √(4x +1) over the interval 0 ≤ x ≤ 2.

  • maths - ,

    (1/2) int (4x+1)^.5 dx from 0 to 2

    (1/2) [(2/(3*4))(4x+1)^1.5] at 2 - at 1

    (1/12) [ (27) - (11.2) ]

    1.32

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