A puddle holds 150 g of water. If 0.50 g of water evaporates from the surface, what is the approximate temperature change of the remaining water? (Lv = 540 cal/g)
1.8`C
To determine the approximate temperature change of the remaining water, we can use the concept of latent heat of vaporization.
The latent heat of vaporization (Lv) is the amount of heat energy required to change the state of a substance from liquid to gas without changing its temperature.
Given that 0.50 g of water evaporates, we can calculate the amount of heat energy required using the formula:
Heat energy (Q) = mass (m) * latent heat of vaporization (Lv)
Q = 0.50 g * 540 cal/g (given Lv = 540 cal/g)
Q ≈ 270 cal
Now, we need to consider the given water remaining in the puddle, which weighs 150 g.
The approximate temperature change can be calculated using the formula:
Temperature change (ΔT) = Heat energy (Q) / (mass (m) * specific heat capacity (c))
The specific heat capacity (c) of water is approximately 1 cal/g°C.
ΔT = 270 cal / (150 g * 1 cal/g°C)
ΔT ≈ 1.8°C
Therefore, the approximate temperature change of the remaining water is approximately 1.8°C.