math
posted by Geoff on .
Given the position function s = 4t^3 − 24t^2 + 6t + 6.
find s and v when a = 0
(Where v is the velocity and a is the acceleration.).

v= ds/dt=12t^248t+6
a= dv/dt=24t48=0 so t=2
find s, v when t=2 
so i just have to sub t=2 in
v = 12t^248t+6 to get v and
s = 4t^324t^2+6t+6 to get s ?