Posted by Jamal on Sunday, December 19, 2010 at 11:38am.
Your solution is not getting the right answers for two or three reasons.
a. You don't have a value for moles Cl2; therefore, you don't have total moles.
b. The moles given are at the start of the reaction (not at equilibrium) BUT total pressure of 2 atm is at equilibrium.
Here is how you approach the problem.
First, notice that you have two moles of products and two moles of reactants; therefore, Kp = Kc. Also note that you don't have a volume; however, moles/volume will give concn BUT the V term cancels in the Kc expression so we can ignore that (and I have ignored it below). You can assume some volume if it makes you feel any better but it cancels in the end, whatever you choose.
........H2 + Cl2 ==> 2HCl
I....0.47.....0.......3.59
C.....+x.....+x.......-2x
E.....0.47+x...x.......3.59-2x
Kp=Kc=(HCl)^2/(H2)(Cl2)
193 = (3.59-2x)^2/(0.47+x)(x)
solve for x.
Add moles to find total moles AT EQUILIBRIUM.
Then X*totalP will find partial pressures of each.
I worked the problem and the answers are correct.
Post your work if you get stuck.
Got it. Thanks man.
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