Posted by **Nancy** on Sunday, December 19, 2010 at 1:01am.

Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling at 110 mph. Train A pases a station at 4:10 a.m. If train B passes the same station at 4:22 a.m., at what time will train B catch up to train A?

- algebra -
**Henry**, Sunday, December 19, 2010 at 11:33am
4:22 - 4:10 = :12 min = 0.2 h = make-up time for train B.

Train A time = t hrs,

Train B time = (t - 0.2) hrs.

d(A) = d(B) = Distance traveled.

100t = 110(t - 0.2),

100t = 110t - 22,

100t - 110t = -22,

-10t = -22,

t = 2.2 hrs,

(t - 0.2) = 2.2 - 0.2 = 2.0 hrs =

time to catchup.

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