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November 27, 2014

November 27, 2014

Posted by **mo** on Saturday, December 18, 2010 at 11:45pm.

- precalc -
**TutorCat**, Sunday, December 19, 2010 at 12:44amhint: what values of x can be?

since you can't have negative numbers under a square root, sqrt(x+6)>or=0

find x

- algebra -
**Alex**, Wednesday, March 2, 2011 at 8:14pmsimplify:

sq rt of 15/5 * sq rt of 20

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