Posted by **George** on Saturday, December 18, 2010 at 6:49pm.

A catapult throws a projectile at a 40.0° angle with a velocity of 26.0 m/s. How high will the projectile reach, and how far away will the projectile land?

- Physics -
**Damon**, Saturday, December 18, 2010 at 7:06pm
u =horizontal speed = 26 cos 40 = 19.9 m/s

Vi initial vertical = 26 sin 40 = 16.7 m/s

time to top:

v = 0 = Vi - 9.8 t

9.8 t = 16.7

t = 1.705 s to top (3.41 s total in air)

HOW HIGH?

h = 0 + Vi t -4.9 t^2

= 16.7(1.705) - 4.9 (1.705)^2

= 28.47 - 14.25

= 14.2 meters

HOW FAR?

u * time in air = 19.9*3.41 = 67.9 m

- Physics -
**George**, Saturday, December 18, 2010 at 7:10pm
A super-hero is leaping from the roof of one building onto another. The first building is 120 meters high and the second building is 80 meters high. The horizontal velocity of the super-hero is 12.0 m/s. What is the maximum possible distance between buildings that the hero can leap across?

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