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October 21, 2014

October 21, 2014

Posted by **George** on Saturday, December 18, 2010 at 6:49pm.

- Physics -
**Damon**, Saturday, December 18, 2010 at 7:06pmu =horizontal speed = 26 cos 40 = 19.9 m/s

Vi initial vertical = 26 sin 40 = 16.7 m/s

time to top:

v = 0 = Vi - 9.8 t

9.8 t = 16.7

t = 1.705 s to top (3.41 s total in air)

HOW HIGH?

h = 0 + Vi t -4.9 t^2

= 16.7(1.705) - 4.9 (1.705)^2

= 28.47 - 14.25

= 14.2 meters

HOW FAR?

u * time in air = 19.9*3.41 = 67.9 m

- Physics -
**George**, Saturday, December 18, 2010 at 7:10pmA super-hero is leaping from the roof of one building onto another. The first building is 120 meters high and the second building is 80 meters high. The horizontal velocity of the super-hero is 12.0 m/s. What is the maximum possible distance between buildings that the hero can leap across?

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