Given the balanced equation representing a reaction:

Cao(s) + CO2(g) ---> CaCO3(s) + heat

What is the total mass of CaO(s) that reacts completely with 88 grams of CO2(g) to produce 200. grams of CaCO3(s)?

I don't understand what you have to do.

its 112g

because if you need a total of 200 and they already tell you that the co2 is 88, then subtract 88 from 200 to get 112

112 grams

To find the total mass of CaO(s) that reacts completely with 88 grams of CO2(g) to produce 200 grams of CaCO3(s), you need to use stoichiometry.

1. Start by writing down the balanced equation for the reaction:

Cao(s) + CO2(g) ---> CaCO3(s) + heat

2. Determine the molar mass of CO2 using the periodic table. Carbon (C) has a molar mass of 12.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol. So CO2 has a molar mass of (12.01 g/mol + 2 * 16.00 g/mol) = 44.01 g/mol.

3. Convert the given mass of CO2 to moles. You can do this by using the equation:

moles = mass / molar mass

moles CO2 = 88 g / 44.01 g/mol = 2 moles

4. Use the stoichiometry of the balanced equation to determine the mole ratio between CaO and CO2. From the balanced equation, you can see that the ratio is 1:1. This means that for every 1 mole of CO2, you have 1 mole of CaO.

5. Calculate the moles of CaO that react. Since the molar ratio is 1:1, the moles of CaO will also be 2 moles.

6. Convert moles of CaO to mass using the equation:

mass = moles * molar mass

mass CaO = 2 moles * (molar mass of CaO)

To find the molar mass of CaO, you can refer to the periodic table. Calcium (Ca) has a molar mass of 40.08 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol. So CaO has a molar mass of (40.08 g/mol + 16.00 g/mol) = 56.08 g/mol.

mass CaO = 2 moles * 56.08 g/mol = 112.16 grams

Therefore, the total mass of CaO that reacts completely with 88 grams of CO2 to produce 200 grams of CaCO3 is 112.16 grams.

This is a stoichiometry problem. Here is a solved example of such a problem. Just follow the steps.

http://www.jiskha.com/science/chemistry/stoichiometry.html