What is the ionic equation for:
2 HClO4(aq) + Mg(OH)2(s) �¨ Mg(ClO4)2(aq) + 2 H2O(l)
2H^+(aq) + 2ClO4^-(aq) + Mg(OH)2(s) ==> Mg^+2(aq) + 2ClO4^-(aq) + H2O(l)
isn't it suppose to be 2H^+(aq) + 2ClO4^-(aq) + Mg(OH)2(s) ==> Mg^+2(aq) + 2ClO4^-(aq) + 2H2O(l)
When I put my answer in the computer it still said it was wrong.
To write the ionic equation for the given reaction, we need to first write the balanced molecular equation:
2 HClO4(aq) + Mg(OH)2(s) → Mg(ClO4)2(aq) + 2 H2O(l)
Now let's break down the reactants and products into their respective ions:
Reactants:
2 HClO4(aq) → 2 H+(aq) + 2 ClO4-(aq)
Mg(OH)2(s) → Mg2+(aq) + 2 OH-(aq)
Products:
Mg(ClO4)2(aq) → Mg2+(aq) + 2 ClO4-(aq)
2 H2O(l) → 2 H+(aq) + 2 OH-(aq)
Now, let's cancel out the spectator ions (ions that appear on both sides of the equation without undergoing a chemical change). In this case, the Mg2+ and ClO4- ions are spectator ions:
Ionic equation:
2 H+(aq) + 2 OH-(aq) → 2 H2O(l)
So, the ionic equation for the given reaction is:
2 H+(aq) + 2 OH-(aq) → 2 H2O(l)
To determine the ionic equation for the given reaction, we need to first write the balanced chemical equation.
The balanced chemical equation for the given reaction is:
2 HClO4(aq) + Mg(OH)2(s) → Mg(ClO4)2(aq) + 2 H2O(l)
To write the ionic equation, we need to separate the reactants and products into their respective ions.
The ions present in the reactants are:
HClO4: H+ and ClO4-
Mg(OH)2: Mg2+ and OH-
The ions present in the products are:
Mg(ClO4)2: Mg2+ and ClO4-
H2O: H+ and OH-
Now let's write the ionic equation by showing only the ions involved in the reaction:
2H+ + 2ClO4- + Mg2+ + 2OH- → Mg2+ + 2ClO4- + 2H2O
In the ionic equation, the spectator ions (ions that are not involved in the reaction) are ClO4- and Mg2+. They appear on both sides of the equation and can be canceled out.
Finally, we can simplify the equation by removing the spectator ions:
2H+ + 2OH- → 2H2O
This is the ionic equation for the given reaction: 2H+ + 2OH- → 2H2O