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February 28, 2015

February 28, 2015

Posted by **akash** on Saturday, December 18, 2010 at 8:15am.

- math -
**bobpursley**, Saturday, December 18, 2010 at 8:39amwell, you know the distance to the base of the tower is 50 m (a 45 deg angle).

Then, you can compute the length of the hypotenuse of that triangle on the common side (ie, 50sqrt2).

now you have one angle (15 deg, one side, and another angle (the 45 deg angle from the tower to the long side 50sqrt2)

Now use the law of sines:

sin15/h=50sqrt2/sin125

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