the distance of D in feet it takes a car traveling at x mph to come to a full stop after hitting the brakes is given by d= 1.26x^2+ .075x. Est. the stopping distance for a car traveling at 40 mph
Substitute 40 for x and solve.
Please help! Car traveling at 35 MPH traveling 900'...how long to stop?
Car traveling at 90 MPH traveling 900'...what is the difference on impact????
To find the stopping distance for a car traveling at 40 mph, you can substitute the value of x = 40 mph into the equation.
The equation for the stopping distance is given as d = 1.26x^2 + 0.075x.
Substituting x = 40 into the equation:
d = 1.26(40)^2 + 0.075(40)
Now, let's calculate:
First, square the value of 40: 40^2 = 1600
Next, multiply 1.26 by 1600: 1.26 * 1600 = 2016
Then, multiply 0.075 by 40: 0.075 * 40 = 3
Now, substitute these values back into the equation:
d = 2016 + 3
Finally, add the values together:
d = 2016 + 3 = 2019
Therefore, the stopping distance for a car traveling at 40 mph is estimated to be 2019 feet.