Posted by **K** on Friday, December 17, 2010 at 9:44am.

An airplane is flying on a compass heading (bearing) of 340 degrees at 325 mph. A wind is blowing with the bearing 320 degrees at 40 mph. Find the component form of the velocity of the airplane. then find the actual ground speed and direction of the plane

- Trig -
**Henry**, Saturday, December 18, 2010 at 3:19pm
Vh = hor = 325cos340 + 40cos320,

Vh = 305 +30.6 = 335.6mph.

Vv = ver = 325sin340 + 40sin320,

Vv = -111.2 -25.7 = -136.9mph.

tanA = Vv/Vh = -136.9 / 335.6 = 0.4080,

A = - 22.2deg CW = 337.8 deg. CCW.

R = Vh / cosA = 335.6 / cos337.8 = 362.5mph @ 337.6 deg.

- Trig -
**dully**, Thursday, February 7, 2013 at 9:35pm
Troll

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