Posted by Sangita on Friday, December 17, 2010 at 7:23am.
The dynamics of the horizontal problem have nothing to do with the falling problem in the vertical direction.
The mass of the ball is also irrelevant.
This is simply something falling 163.8 meters, period.
163.8 = (1/2)(9.81) t^2
solve for t
Perhaps later there is a part two where you will be asked how far from a point directly under the drop the ball lands, but that has not been asked yet.
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