Posted by julia on .
23. A 32.3 L sample of a gas at 305oC and 1.20 atm is to be cooled at constant pressure until its volume becomes 28.4L. What will be the new gas temperature?
Tf = Vf*Ti/Vi
Tf =28.4L x (305+273)K / 32.3L
= (28.4)(578)K / 32.3
= 16415.2/32.3
Tf = 508K
I got this one wrong on a test please let me know what I'm doing wrong???

chem/plz/check work studying for a final 
DrBob222,
I get 508.2 K which rounds to 508 K. I don't see anything wrong with what you've done. Perhaps the answer was supposed to be in celsius.