How many moles of Mg are there in 4.00 L of a 0.500 M solution of MgCl2?
what is .5M*4L ?
ok simple enough, if the question asked for moles of Cl would i just use 1M instead of .5M?
Well, if it asked for moles of the Cl ION, yes, double it.
To find the number of moles of Mg in the solution, we will use the equation:
moles of solute = concentration × volume
Given:
- Concentration of MgCl2 solution = 0.500 M (moles per liter)
- Volume of MgCl2 solution = 4.00 L
First, we need to determine the number of moles of MgCl2 in the solution. Since MgCl2 has two chloride ions and one magnesium ion, we need to multiply the concentration of MgCl2 by 2:
moles of MgCl2 = concentration of MgCl2 × volume
= 0.500 M × 4.00 L
= 2.00 moles of MgCl2
Next, we can determine the number of moles of Mg by multiplying the moles of MgCl2 by the ratio of moles of Mg to moles of MgCl2. Since there is one magnesium ion per one magnesium chloride ion:
moles of Mg = moles of MgCl2 × (1 mole of Mg / 1 mole of MgCl2)
= 2.00 moles of MgCl2 × (1 mole of Mg / 1 mole of MgCl2)
= 2.00 moles of Mg
Therefore, there are 2.00 moles of Mg in 4.00 L of a 0.500 M solution of MgCl2.