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Posted by on Wednesday, December 15, 2010 at 9:08pm.

A researcher put 10.0 moles of N2O into a 2-L container at some temperature where it decomposes according to the following: N2O = 2N2+ O2. At equilibrium 2.20 moles of N2O remain. Calculate the Kc for the reaction.

  • chemistry - , Wednesday, December 15, 2010 at 9:23pm

    You didn't balance the equation.
    Set up an ICE chart. (N2O) initially = 10.0moles/2L = 5M
    ............2N2O ==> 2N2 + O2
    initial.....10.0M....0......0
    change.......-x......+2x...+x
    equilibrium..10.00-x..2x....x

    Kc = (N2)^2(O2)/(N2O)^2

    You are given that at equilibrium the N2O is 2.20 moles.
    10.00-x = 2.20, solve for x and complete the table. Convert moles to M in all cases and substitute into Kc expression and solve for Kc.

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