Friday
April 18, 2014

Homework Help: CHEMISTRY TITRATION Q

Posted by LISA on Wednesday, December 15, 2010 at 2:30pm.

The titration of 25.00mL of Ba(OH)2 solution with an aqueous solution of 0.500 M HCl reaches an end point when 30.20 mL of the HCl solution is added. Determine the concentration of M of the Ba(OH)2 solution.


Soo 25.00mL=0.025L
30.20mL= 0.0302L

moles= MxL (0.500M)(0.0302L)=0.5302 moles of HCl and since the moles are the same at the end point than 0.5302 is moles of Ba(OH)2 too?

M=moles Ba(OH)2/initial L 0.5302/0.025L= 21.2M is my answer

but the book says the answer is 0.302M
what have I done wrong?? Thanks!!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - In a titration experiment, 22.00mL of a NaOH solution are required ...
chemistry - A flask containing 5.00mL of 3 M HCl solution requires 14.45mL of 1....
chemistry - A flask containing 5.00mL of 3 M HCl solution requires 14.45mL of 1....
Chemistry - A 20.0 ml sample of an unknown HCl solution requires titration with ...
chemistry - Determine the Molarity of a 125 mL NaOH solution if upon titration ...
chemistry - 11.During an acid-base titration, 25 mL of NaOH 0.2 M were required ...
chemistry - CH3NH2(aq)+H2O(l)=>CH3NH3+(aq)+OH-(aq) Kb=4.4 x 10^-4 Methylamine...
chemistry - In Chemistry: what is ph during the titration of 20.00ml of 0.1000m ...
AP Chemistry - CH3NH2(aq)+H2O(l)=>CH3NH3+(aq)+OH-(aq) Kb=4.4 x 10^-4 ...
Chemistry - 10.0 mL of a 0.300M NH3 solution is titrated with a 0.100M HCl ...

Search
Members