Posted by Bogdanam on .
The heat of combustion of bituminous coal is 2.50 × 104 J/g. What quantity of the coal is required to produce the energy to convert 137.7 pounds of ice at 0.00°C to steam at 100.°C?
specific heat (ice) = 2.10 J/g°C
specific heat (water) = 4.18 J/g°C
heat of fusion = 333 J/g
heat of vaporization = 2258 J/g
A) 7.52 kg
B) 0.832 kg
C) 1.044 kg
D) 5.64 kg
E) 1.88 kg
A long problem. How much do you know how to do? Can you calculate the heat required to convert ice to steam?