Posted by **trina** on Wednesday, December 15, 2010 at 10:42am.

can anyone explain how to divide in algebra? I have this problem:

(15x2-24+9)/(3x-3)

I am not looking for someone to give me the answer straight out I just need to know how to get there.

- 12th grade -
**Dr Russ**, Wednesday, December 15, 2010 at 10:52am
Start in the same way as you would do long division.

Set it up as

_________

(3x-3)|15x2-24x+9

then how many times does 3x go into 15x^2, which is 5x

5x

_________

(3x-3)|15x2-24x+9

15x2-15x (from 5x times (3x-3)

subtract

5x

_________

(3x-3)|15x2-24x+9

15x2-15x

________

-9x+9

I hope the formatting holds. Is this OK?

- 12th grade -
**Dr Russ**, Wednesday, December 15, 2010 at 10:55am
The formatting didn't work 8-((

I hope you get the idea. I'll try again with dots for spaces.

Start in the same way as you would do long division.

Set it up as

......_________

(3x-3)|15x2-24x+9

then how many times does 3x go into 15x^2, which is 5x

.......5x

......._________

(3x-3)|15x2-24x+9

.......15x2-15x (from 5x times (3x-3)

subtract

.......5x

......._________

(3x-3)|15x2-24x+9

.......15x2-15x

............________

............-9x+9

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