A sample containing 1.2x10^-2 mol HCl is completely neutralized by 100.0mL of Sr(OH)2 what is the [Sr(OH)2]?
Do you mean, "What is the M of the Sr(OH)2?
moles HCl = 0.012.
2HCl + Sr(OH)2 ==> SrCl2 + 2H2O
moles Sr(OH)2 = 1/2 mole HCl
[Sr(OH)2] = moles/L
To determine the concentration of Sr(OH)2, we first need to calculate the number of moles of Sr(OH)2 used to neutralize the HCl.
According to the balanced chemical equation for the reaction between HCl and Sr(OH)2:
2 HCl + Sr(OH)2 -> SrCl2 + 2 H2O
We can see that the stoichiometric ratio between HCl and Sr(OH)2 is 2:1. This means that 2 moles of HCl react with 1 mole of Sr(OH)2.
Given that the sample contains 1.2x10^-2 mol of HCl, we can infer that half that amount, or 6.0x10^-3 mol of Sr(OH)2, was used for neutralization.
Next, we need to calculate the concentration of Sr(OH)2 in the solution. We have been given that 100.0 mL of Sr(OH)2 was used.
Concentration can be calculated using the formula:
Concentration (in mol/L) = Number of moles / Volume (in L)
Converting the volume of Sr(OH)2 from milliliters to liters:
100.0 mL = 100.0 mL × (1 L / 1000 mL) = 0.100 L
Now, we can calculate the concentration:
Concentration = 6.0x10^-3 mol / 0.100 L = 0.060 mol/L
Therefore, the concentration of Sr(OH)2 in the solution is 0.060 mol/L or 0.060 M.
To find the concentration of Sr(OH)2 in the given solution, we need to first determine the number of moles of Sr(OH)2.
First, we need to determine the number of moles of HCl:
Moles of HCl = 1.2 x 10^-2 mol
Since HCl and Sr(OH)2 react in a 1:2 ratio, the molar ratio is 1:2. This means that one mole of HCl reacts with two moles of Sr(OH)2. Therefore, the number of moles of Sr(OH)2 is:
Moles of Sr(OH)2 = 1.2 x 10^-2 mol / 2 = 6.0 x 10^-3 mol
Next, we need to determine the volume of Sr(OH)2 solution. Given that the volume of Sr(OH)2 solution is 100.0 mL, we need to convert it to liters:
Volume of Sr(OH)2 solution = 100.0 mL = 100.0 mL * (1 L / 1000 mL) = 0.100 L
Now, we can calculate the concentration of Sr(OH)2 by dividing the number of moles by the volume:
[Sr(OH)2] = Moles of Sr(OH)2 / Volume of Sr(OH)2 solution
= 6.0 x 10^-3 mol / 0.100 L
= 0.060 M
Therefore, the concentration of Sr(OH)2 in the solution is 0.060 M.