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September 30, 2014

September 30, 2014

Posted by **Robert C** on Tuesday, December 14, 2010 at 11:04pm.

θ = (0.0800 rad) cos[(4.30 rad/s)t + ϕ]

(a) What is the pendulum's length?

(b) What is its maximum kinetic energy?

- Physics -
**Robert C**, Tuesday, December 14, 2010 at 11:08pmI figured out a) by using w=2pi/T

T=1.46 then used T to solved T=(2pi*sq root L/g) L = .53 but I can't figure out an equation to give me the velocity. Any ideas?

- Physics -
**drwls**, Tuesday, December 14, 2010 at 11:10pm(a) w = 4.40 rad/s

is the angular frequency, sqrt(g/L)

Solve for L, the pendulum length

L = g/w^2

(b) Max velocity Vmax = = L*theta*w

Maximum KE = (1/2) M Vmax^2

- Physics -
**drwls**, Tuesday, December 14, 2010 at 11:16pmYou are right about L = 0.53. Don't forget the units (meters)

In simple harmonic motion,

max velocity = w*(Amplitude) and

max acceleration = w^2*(Ampitude)

In your case I had to add an L factor to get linear velocities from the angular amplitude.

- Physics -
**Robert C**, Tuesday, December 14, 2010 at 11:18pmWhere did the Vmax = L*theta*w

come from? How do I find theta?

- Physics -
**drwls**, Tuesday, December 14, 2010 at 11:21pmTheta should be theta-max, the angular amplitude, which is 0.0800 radians

Sorry about that

- Physics -
**Robert C**, Tuesday, December 14, 2010 at 11:28pmVmax= (.53m)(.0800rad)(4.30 rad/s)

=.182

KE=1/2mv^2

=1/2(.066kg)(.182)^2

=.0011 or 1.09e-03

That doesn't look right to me. what am I doing wrong? ;_;

- Physics -
**Robert C**, Tuesday, December 14, 2010 at 11:32pmAnother question, sorry, trying my bests to understand your thinking. I don't see where you knew to multiple L * theta * W.

I understand that the 2nd derivative of the equation gives you the Velocity function.

- Physics -
**drwls**, Wednesday, December 15, 2010 at 1:32amNo, the first derivative of your theta vs t (multiplied by L) gives you the velocity function.

L*theta_max is the displacement amplitude (in small angle approximation) ; so

w*L*theta_max

is the maximum velocity

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