Posted by **Liz** on Tuesday, December 14, 2010 at 10:15pm.

Find d^2y/dx^2 by implicit differentiation.

x^(1/3) + y^(1/3) = 4

I know that first you must find the 1st derivative & for y prime I got 1/3x^(-2/3) + 1/3y^(-2/3) dy/dx = 0

Then for dy/dx I got

dy/dx = [-1/3x^(-2/3)] / [1/3y^(-2/3)]

I think that from here I would use the quotient rule to find the second derivative?

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