Calcium carbonate reacts w/stomach acid according to the following chemical equation.
CaCO3+2HCl(aq)-> CaCl2(aq)+H2O(l)+CO2(g)
A. Balance the eqaution
B. Tums is one commercially sold antacid that contains CACO3. If Tums is added to 20.0ml of 0.400 M HCl, how many grams of carbon dioxide gas are produced?
The equation is balanced.
B. Mass tums = ?? %CaCO3 in tums = ??
Mass CO2 produced depends upon the amount of CaCO3 in tums; however, no more than 0.176 g CO2 can be produced from 20.0 mL of 0.400 M acid.
moles HCl = 0.020 x 0.400 = 0.008 moles.
moles CO2 = moles HCl x (1 mole CO2/2 moles HCl) = 0.008*1/2 = 0.004 moles CO2
grams CO2 = moles x molar mass = 0.004 x 44 g/mol = ??
A. To balance the equation, we start by ensuring that the number of atoms of each element is the same on both sides of the equation.
CaCO3 + 2HCl(aq) -> CaCl2(aq) + H2O(l) + CO2(g)
In this equation, there is one calcium (Ca) atom on the left side and one calcium atom on the right side. The carbon (C) atoms are also balanced, as there is one on each side. However, the oxygen (O) atoms are not balanced, with three on the left side and only one on the right side.
To balance the equation, we can add a coefficient of 3 in front of HCl, which will give us:
CaCO3 + 3HCl(aq) -> CaCl2(aq) + H2O(l) + CO2(g)
Now the equation is balanced, with one calcium atom, one carbon atom, and three oxygen atoms on each side.
B. To determine the number of grams of carbon dioxide (CO2) gas produced, we need to use stoichiometry. Stoichiometry is a branch of chemistry that relates the quantities of reactants and products in a chemical reaction.
First, let's convert the volume of the HCl solution (20.0 ml) to moles. We can use the molarity (0.400 M) and the formula:
moles = volume (in liters) x molarity
Since the volume is given in milliliters, we need to convert it to liters:
20.0 ml = 20.0 ml x (1 L / 1000 ml) = 0.0200 L
Now we can calculate the moles of HCl:
moles of HCl = 0.0200 L x 0.400 mol/L = 0.00800 mol
According to the balanced equation, the stoichiometric ratio between HCl and CO2 is 2:1. That means for every 2 moles of HCl, 1 mole of CO2 is produced.
Therefore, the moles of CO2 produced can be calculated as:
moles of CO2 = (moles of HCl / 2) = 0.00800 mol / 2 = 0.00400 mol
Finally, we can convert moles of CO2 to grams using the molar mass of carbon dioxide (44.01 g/mol):
grams of CO2 = moles of CO2 x molar mass of CO2
grams of CO2 = 0.00400 mol x 44.01 g/mol = 0.176 g
So, when Tums is added to 20.0 ml of 0.400 M HCl, approximately 0.176 grams of carbon dioxide gas are produced.
A. To balance the equation, make sure that the number of atoms of each element is the same on both sides of the equation.
CaCO3 + 2HCl(aq) -> CaCl2(aq) + H2O(l) + CO2(g)
The equation is already balanced.
B. To find the number of grams of carbon dioxide gas produced, we will first calculate the number of moles of HCl used and then use stoichiometry to find the number of moles of CO2 produced.
First, calculate the number of moles of HCl used:
Number of moles = concentration (mol/L) x volume (L)
Number of moles HCl = 0.400 mol/L x (20.0 mL / 1000 mL/L) [Convert mL to L]
Number of moles HCl = 0.008 mol
According to the balanced equation, 1 mole of HCl reacts with 1 mole of CaCO3, producing 1 mole of CO2. Therefore, the number of moles of CO2 produced is also 0.008 mol.
To find the mass of CO2, we need to use the molar mass of CO2, which is approximately 44.01 g/mol.
Mass of CO2 = number of moles x molar mass
Mass of CO2 = 0.008 mol x 44.01 g/mol
Mass of CO2 = 0.352 g
Therefore, approximately 0.352 grams of carbon dioxide gas are produced when Tums is added to 20.0 mL of 0.400 M HCl.