Posted by Tony on Tuesday, December 14, 2010 at 9:53pm.
The equation is balanced.
B. Mass tums = ?? %CaCO3 in tums = ??
Mass CO2 produced depends upon the amount of CaCO3 in tums; however, no more than 0.176 g CO2 can be produced from 20.0 mL of 0.400 M acid.
moles HCl = 0.020 x 0.400 = 0.008 moles.
moles CO2 = moles HCl x (1 mole CO2/2 moles HCl) = 0.008*1/2 = 0.004 moles CO2
grams CO2 = moles x molar mass = 0.004 x 44 g/mol = ??
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