If 150 g of water are heated from 20.ºC to 30. ºC,the nunber of joules of heat energy absored is

q=mct c is the specific heat in j per gram times degree celsius

150g*(4.18)(10)=6270 J

Well, well, well, looks like we have a temperature, I mean, a question about heat! Let's get cooking!

To determine the amount of heat energy absorbed, we can use the formula: Q = mcΔT, where Q represents the heat energy, m is the mass, c is the specific heat capacity (which is about 4.18 J/g°C for water), and ΔT is the change in temperature.

So, with a mass of 150 g, a specific heat capacity of 4.18 J/g°C, and a change in temperature of 10°C (30°C - 20°C), let's plug these juicy numbers into the formula:

Q = (150 g) x (4.18 J/g°C) x (10°C)

And after some math magic, we get:

Q = 6270 J

Voila! The number of joules of heat energy absorbed is 6270 J. Stay cool and keep heating up those questions!

To calculate the amount of heat energy absorbed, we can use the formula:

Q = mcΔT

Where:
Q represents the heat energy absorbed,
m represents the mass of the substance (in this case, water),
c represents the specific heat capacity of water,
ΔT represents the change in temperature.

Given:
Mass of water, m = 150 g
Initial temperature, T1 = 20.ºC
Final temperature, T2 = 30. ºC

First, we need to find the change in temperature:

ΔT = T2 - T1
ΔT = 30 ºC - 20 ºC
ΔT = 10 ºC

Now, we need to find the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.

Using the formula Q = mcΔT:

Q = (150 g) * (4.18 J/g°C) * (10 ºC)

Q = 6270 J

Therefore, the number of joules of heat energy absorbed is 6270 J.

To calculate the amount of heat energy absorbed by the water, you can use the formula:

Q = mcΔT

where Q represents the heat energy, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

In this case, the mass of water is given as 150 g, the specific heat capacity of water is approximately 4.18 J/g·°C, and the change in temperature is 30°C - 20°C = 10°C.

Let's substitute these values into the formula:

Q = (150 g) × (4.18 J/g·°C) × (10°C)

Simplifying the equation:

Q = 6270 J

Therefore, the number of joules of heat energy absorbed by the water is 6270 J.