How many calories are required to raise the temperature of 75 grams of water from 20 degrees C to 50 degrees C?
q = mass x specific heat x delta T.
Well, let me ask you this: have you ever seen a calorie in the wild? They're quite rare, you know. But to give you a rough idea, it takes approximately 4.184 joules to raise the temperature of one gram of water by one degree Celsius. So, let's put on our imaginary chef hats and calculate this. We have 75 grams of water, and we need to raise its temperature by 30 degrees Celsius. Are you ready for this? Drumroll, please... you're looking at approximately 94,020 imaginary calories! Now, who's hungry?
To calculate the number of calories required to raise the temperature of a substance, you can use the equation:
q = mcΔT
where:
q is the heat energy in calories
m is the mass of the substance in grams
c is the specific heat capacity of the substance in calories/gram°C
ΔT is the change in temperature in degrees Celsius
In this case, the mass (m) of water is 75 grams. The specific heat capacity (c) of water is approximately 1 calorie/gram°C. The change in temperature (ΔT) is 50°C - 20°C = 30°C.
Now, substituting the given values into the equation:
q = 75 grams * 1 calorie/gram°C * 30°C
q = 2250 calories
Therefore, it would require 2250 calories to raise the temperature of 75 grams of water from 20 degrees Celsius to 50 degrees Celsius.
To calculate the number of calories required to raise the temperature of water, we'll need to use the specific heat capacity of water. The specific heat capacity of water is approximately 1 calorie/gram°C.
The formula to calculate the amount of heat energy required is:
Q = m * c * ΔT
where:
Q = heat energy (in calories)
m = mass of the water (in grams)
c = specific heat capacity of water (1 calorie/gram°C)
ΔT = change in temperature (in °C)
In this case, the mass of water (m) is 75 grams, the specific heat capacity of water (c) is 1 calorie/gram°C, and the change in temperature (ΔT) is 50°C - 20°C = 30°C.
Now, let's calculate the heat energy (Q):
Q = 75 grams * 1 calorie/gram°C * 30°C
Q = 2250 calories
Therefore, it would require 2250 calories to raise the temperature of 75 grams of water from 20°C to 50°C.