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Posted by **STACY** on Tuesday, December 14, 2010 at 4:41pm.

Consider an aqueous solution prepared from 250.0 mL of water and 1.27 g of potassium bromide. Express the amount of potassium bromide in this solution in terms of

(a) mass percent

(b) mole fraction

(c) molarity

assume the density of the solution is equal to that of water, 1.00 g mL-1.........help!

CHEMISTRY - DrBob222, Monday, December 13, 2010 at 8:54pm

Surely you don't want me to work all three. Surely you know SOMETHING about SOME of them. Just remember the definitions:

1. mass percent. grams solute/100 g solution.

2. mole fraction. moles solute/total mules.

3. molarity = moles/L of solution.

Apply those three definitions and you will have your answer(s).

Post your work if you get stuck.

CHEMISTRY - STACY, Tuesday, December 14, 2010 at 4:40pm

I surely do, and don't call me Shirley! LOL yessss i'm sorry I don't know much about chemistry that's why i'm here!!

1. Mass percent= grams solute/100solution 1.27g/250.0mL = 5.08x10^-03 is my answer but the correct one is 0.505%

2. Mole fraction= moles solute/total moles ?/119.002

3. Molarity 1.27g/119.002= 0.0107moles

than 0.0107/0.25L = 0.048 that's my answer but the correct one is 4.25x10^-2

- chemisty -
**DrBob222**, Tuesday, December 14, 2010 at 5:54pmIf your name is really Stacy, that's a pretty name, and I wouldn't think of calling you Shirley.

We welcome you back any time but we want to know how you would approach the problems and/or what you know and what you don't understand.

1. mass percent = mass solute/100 g solution.

We have 1.27 g KBr and we have that in 250 mL H2O(250 g).

So the total mass of solution is 250g + 1.27 g = 251.27 g.

mass percent = (1.27/251.27)*100 = 0.505% w/w. (You get 0.508 if you forget to add 250 gH2O + 1.27 g KBr = total mass 251.27. That's easy to forget (I know because I sometimes forget) so be careful with these.

2. moles KBr = 1.27g/119 = 0.01067

moles H2O in 250 g = 250/18.015 = 13.877.

mole fraction KBr = moles KBr/total moles. You can finish.

3. M = moles/L. I don't get your answer. You just read your calculator wrong. If I do the math with your numbers I obtained 0.0428; I think you just skipped the 2 when you read it.

If the density of the solution is 1.00 g/mL, then the volume of the solution is volume = mass/density = 251.27/1.00 = 251.27 (go back and re-read how we arrived at that), so M = moles/L and M = 0.01067/0.25127 = 0.04246 M which rounds to 0.0425 M. - chemisty -
**STACY**, Tuesday, December 14, 2010 at 8:44pmThanks! and No Stacy is not my real name, although Shirley is my mothers name LOL!