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November 22, 2014

Homework Help: chemistry

Posted by STACY on Tuesday, December 14, 2010 at 4:17pm.

how many grams of sodium carbonate are needed to prepare 0.250 L of an 0.100 M aqueous solution of sodium ions?

well normally you go moles=grams/molar mass than M= moles/L

but when looking for grams? what do you do........multiple .250 by .100 than divide by the molar mass of 105.988??



CHEMISTRY - DrBob222, Monday, December 13, 2010 at 8:51pm
You work the problem backwards.
moles = M x L.
Solve for moles. You got that far.

Then moles = grams/molar mass.
MULTIPLY (not divide) moles x molar mass.



CHEMISTRY - STACY, Tuesday, December 14, 2010 at 4:12pm
Soooo

Moles= MxL (0.100M)(0.250L)=0.025

than multiply moles by molar mass
(0.025)(105.988)= 2.65g

So my answer is 2.65g but the book says it's 1.32g? What am I overlooking.....man I hate chemistry =(

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