Posted by ama on Tuesday, December 14, 2010 at 11:52am.
a hockey puck is given the initial speed of 10 m/s. If the coefficient of kinetic friction between the ice and puck is 0.10, how far will the puck slide before stopping?

physics  bobpursley, Tuesday, December 14, 2010 at 12:03pm
KE= energy in friction
1/2 m v^2=mu*mg*distance
solve for distance.

physics  David, Tuesday, December 14, 2010 at 1:19pm
Ffg

physics  Jamar, Wednesday, September 21, 2011 at 8:44am
What you wanna do is snort a line, smoke a J and look beyond what you see

physics  Brock, Tuesday, November 15, 2011 at 5:34pm
HAHA!

Physics  Dan, Saturday, January 9, 2016 at 11:58pm
f = ma
u(k) * f(normal) = m*a
u(k) *m*g=m*a
u(k) *g =a
a = 0.10 * 9.81m/s^2 = 0.981 m/s^2
this is defined to be a negative acceleration
v = u + a*t
so t = (vu)/a
and x = t * (v+u)/2
so together x = (v+u)(vu)/2a
where x = distance, v = final speed, u = initial speed, t = time, a = acceleration
substitute in our known values:
x = (0+10)(010)/(2*0.981)
x = 50/0.981 = 50.97m
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