Posted by **ama** on Tuesday, December 14, 2010 at 11:52am.

a hockey puck is given the initial speed of 10 m/s. If the coefficient of kinetic friction between the ice and puck is 0.10, how far will the puck slide before stopping?

- physics -
**bobpursley**, Tuesday, December 14, 2010 at 12:03pm
KE= energy in friction

1/2 m v^2=mu*mg*distance

solve for distance.

- physics -
**David**, Tuesday, December 14, 2010 at 1:19pm
Ffg

- physics -
**Jamar**, Wednesday, September 21, 2011 at 8:44am
What you wanna do is snort a line, smoke a J and look beyond what you see

- physics -
**Brock**, Tuesday, November 15, 2011 at 5:34pm
HAHA!

- Physics -
**Dan**, Saturday, January 9, 2016 at 11:58pm
f = ma

u(k) * f(normal) = m*a

u(k) *m*g=m*a

u(k) *g =a

a = 0.10 * 9.81m/s^2 = 0.981 m/s^2

this is defined to be a negative acceleration

v = u + a*t

so t = (v-u)/a

and x = t * (v+u)/2

so together x = (v+u)(v-u)/2a

where x = distance, v = final speed, u = initial speed, t = time, a = acceleration

substitute in our known values:

x = (0+10)(0-10)/(2*-0.981)

x = 50/0.981 = 50.97m

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