How much water would you add to 12 M HCl to make 650 mL of 1.5 M HCl? Hint: This is a dilution problem
you are diluting it 12/1.5 times, or 8 times.
8 times means one part original, seven parts water.
well, 8 parts makes 650ml, so one part is 650/8=81.25 ml of acid, then
7 parts water (7*81.25 or 650-81.25) 569ml
Your teacher is too easy.
Agreed it is a dilution problem. There is however a problem with the wording as it is not good practice to add water to the concentrated acid.
if we use
M1V1=M2V2
then
12V1=650x1.5
to find the initial volume (V1) of the 12 M needed
The volume of water to which the 12 M HCl is added is then 650 ml-V1.
Bob types faster than me!!
To solve this dilution problem, we can use the formula:
M1V1 = M2V2
Where:
M1 is the initial concentration of the solution (12 M in this case)
V1 is the initial volume of the solution (unknown)
M2 is the final concentration of the solution (1.5 M in this case)
V2 is the final volume of the solution (650 mL in this case)
Let's rearrange the formula to solve for V1:
V1 = (M2 * V2) / M1
Substituting the given values:
V1 = (1.5 M * 650 mL) / 12 M
Using this formula, we can calculate V1:
V1 = (975 mL*mol) / 12 M
V1 ≈ 81.25 mL
Therefore, you would add approximately 81.25 mL of water to 12 M HCl to make 650 mL of 1.5 M HCl.