Posted by lianne on Tuesday, December 14, 2010 at 6:21am.
24Cr is 1s2 2s2 2p6 3s2 3p6 3d5 4s1
For Cr^+, remove the 4s1 electron.
For Cr^+2, remove 4s1 and one 3d5
Thereafter, remove as many 3d electrons as needed.
Cr^+6 is 1s2 2s2 2p6 3s2 3p6 3d0 4s0
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