Thursday

October 30, 2014

October 30, 2014

Posted by **SKipper** on Tuesday, December 14, 2010 at 12:25am.

Prove: Ad is the median to BC

- geometry proofs -
**MathMate**, Tuesday, December 14, 2010 at 9:02amConsider triangles ABd and ACd for congruence:

Ad is altitude, so

∠ABd = ∠ACd = 90°

Ad bisects angle BAC, so

∠CAd = ∠BAd

Ad = Ad (common side)

So triangles ABd and ACd are congruent, ASA (angle-side-angle).

**Answer this Question**

**Related Questions**

Geometry / Proofs - Given: Triangle ABC with AD bisecting angle BAC, and AE is ...

Math(Geometry) - In the diagram below(no diagram but details will be provided), ...

GEOMETRY - GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC

Geometry - Indirect Proofs Prove a triangle cannot have 2 right angles. 1) Given...

Math (Geometry) - ABC is a triangle with a right angle at A. M and N are points ...

Math (Geometry) - ABC is a triangle with a right angle at A. M and N are points ...

Geometry - Can you help me with Always, Sometimes, Never questions?? I have ...

Geometry Honors - Can someone help me with Always, Sometimes, Never questions?? ...

maths - in triangle abc angle b = 2angle c.d is a point ob bc such that ad ...

geometry - Points D, E, and F are the midpoints of sides \overline{BC}, \...