Posted by Anna on Monday, December 13, 2010 at 10:31pm.
Hi Reiny, I posted this problem earlier and you responded but I don't get the reasoning
The problem was 2log8(x+1) = 8
you said multiply by 2
and then you put log8(x+1)=4(wasn't that dividing by 2)
log8(x+1)^2 = 8 (how did you get to the power of 2 and =4 became =8
x+1 = 8^4
x= 4095
Thank you

AlgebraReiny please explain this  Reiny, Monday, December 13, 2010 at 10:43pm
Of course I should have said divide by 2
I started by putting the 2 as an exponent, but then changed my mind.
I forgot to delete the line log8(x+1)^2 = 8 from that approach
here is the simple solution
2log8(x+1) = 8
first of all, divide be 2
log8(x+1) = 4
(x+1) = 8^4 , by definition of logs
x+1 = 4096
x = 4095

AlgebraReiny please explain this  Anna, Monday, December 13, 2010 at 10:46pm
Reiny, thank youI get it now
thanks again
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